Keeli was asked to approximate the square root of 38 to the nearest whole number.

Her work is shown here. Analyze her work, describing what she did correctly and what she did incorrectly. Provide the correct approximation, showing and explaining your work.

If you need to type the square root symbol (for example, √36), either type it in words, as in "the square root of 36," or use the common abbreviation "sqrt," as in "sqrt (36) " or "sqrt 36."

38 is between the two perfect squares 36 and 64.

38 is closer to 36 than it is to 64.

So 38=6

... ?

Question

Mathematics

Madalyn Pace

28 July, 00:08

Keeli was asked to approximate the square root of 38 to the nearest whole number.

Her work is shown here. Analyze her work, describing what she did correctly and what she did incorrectly. Provide the correct approximation, showing and explaining your work.

If you need to type the square root symbol (for example, √36), either type it in words, as in "the square root of 36," or use the common abbreviation "sqrt," as in "sqrt (36) " or "sqrt 36."

38 is between the two perfect squares 36 and 64.

38 is closer to 36 than it is to 64.

So 38=6

... ?

+5

Answers (1)

Know the Answer?

Patch · Answer 1

We know that 36<38<64

so sqrt36 < sqrt 38 < sqrt 64 it is equivalent to 6< sqrt38 < 8

since 38 is closer to 36 than it is to 64, so 6 is approximate the square root of 38 as a whole number