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13 May, 02:49

How do you solve x^2-7=4x^2+5

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  1. 13 May, 05:59
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    No solution OR 2i

    Step-by-step explanation:

    x^2-7=4x^2+5

    x^2-4x^2=5+7 - combine like terms

    -3x^2=12 divide by negative 1

    3x^2=-12 divide by 3 to isolate x.

    x^2=-4

    to get rid of the power, we have to square root, but since we cant square root a negative, it becomes no solution.

    In case your teacher wants imaginary numbers as part of the solution

    You would get x=2i
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