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27 October, 14:09

For the equation below, determine its order. Name the independent variable, the dependent variable, and any parameters in the equation. (Enter your answers as comma-separated lists. If an answer does not exist, enter DNE.) mx'' + bx' + kx = 8t6, assuming x is a function of t

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  1. 27 October, 14:21
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    The equation is an differential equation of second order.

    The dependent variable is x, while t is the independent variable.

    Step-by-step explanation:

    The order of the equation depends on the greatest grade of the derivative, in this case it's the second derivative (x'')

    Since x is a function of t, we would have that t is the independent variable while x is the dependent variable.
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