Ask Question
3 November, 23:50

VThe Mathematics Club will select a president, a vice president, and a treasurer for the club. If there are 15 members in the club, how many different selections of a president, a vice president, and a treasurer are possible if each club member can be selected to only one position?

+3
Answers (1)
  1. 4 November, 02:44
    0
    2730 different selections

    Step-by-step explanation:

    This problem is solved using permutations: it is similar to combination, but the order of each element matters (if person A is president, person B is vice and person C is treasurer, this is a different case from a case where person A is vice, person B is treasurer and person C is president)

    The formula of permutation is:

    P = n! / (n-p) !

    where n is the total number of members in this case (15), and p is the number of different positions (3).

    So, the number of different selections is:

    P = 15!/12! = 15*14*13 = 2730 different selections
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “VThe Mathematics Club will select a president, a vice president, and a treasurer for the club. If there are 15 members in the club, how ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers