Ask Question
16 June, 00:48

In a group of 270 college students, it is found that 64 like brussels sprouts, 94 like broccoli, 58 like cauliflower, 26 like both brussels sprouts and broccoli, 28 like both brusselssprouts and cauliflower, 22 like both broccoli and cauliflower, and 14 like all three vegetables.

How many of the 270 students do not like any of these vegetables?

+2
Answers (1)
  1. 16 June, 03:10
    0
    116 students

    Step-by-step explanation:

    we let

    U=[Total number of students ]

    This implies that,

    n (U) = 270

    B. S=[Those who like brussels sprouts ]

    This implies that,

    n (B. S) = 64

    B=[Those who like broccoli]

    This implies that,

    n (B) = 94

    C=[Those who like cauliflower]

    This implies that,

    n (C) = 58

    Using the formula:

    n (U) = n (B. S) + n (B) + n (C) - n (B. S n B) - n (B. S n C) - n (B n C) + n (B. S n C n B) + n (no set)

    By substitution we get,

    270=64+94+58-26-28-22+14+n (no set)

    270=154+n (no set)

    270-154=n (no set)

    n (no set) = 116

    Hence number of students who do not like any of the three vegetables is 116
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In a group of 270 college students, it is found that 64 like brussels sprouts, 94 like broccoli, 58 like cauliflower, 26 like both brussels ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers