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31 August, 00:03

Solve a+b=9; 2b+2c=13; 2a-c=11 unknowly

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  1. 31 August, 00:37
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    Answer: a = 17/2 and b = 1/2 and c = 6

    Step-by-step explanation:

    the system is : a+b=9 ... (1)

    2b+2c=13 ... (2)

    2a-c=11 ... (3)

    by (1) and (2) calculate : a and b

    by (3) : 2a = 11 + c

    so : a = (11+c) / 2 ... (*)

    by (2) : 2b = 13 - 2c

    so : b = (13-2c) / 2 ... (**)

    put the value for a and b by (*) and (**) in (1):

    (11+c) / 2. + (13-2c) / 2 = 9

    (11+c + 13-2c) / 2 = 9

    24-c = 18

    c = 24-18

    c = 6

    put this value in (*) and (**)

    a = (11+6) / 2

    a = 17/2

    b = (13-12) / 2

    b = 1/2

    yoi can verify : 1) a+b = 9 : 17/2 + 1/2 = 18/2 = 9 ... right

    2) 2b+2c=13 : 2 (1/2) + 2 (6) = 1+12 = 13 ... right

    3) 2a-c=11 : 2 (17/2) - 6 = 17-6 = 13 ... right
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