Find the zero of the polynomial function x^3+8x^2-11x-18

The answer to your question is: (x - 2) (x + 9) (x + 1)

Step-by-step explanation:

x³ + 8x² - 11x - 18

find the prime factors of 18

18 2

9 3 Try : ± 1, ±2, ±3, ± 6,± 9

3 3

1

Synthetic division

1 8 - 11 - 18 2

2 20 18

1 10 9 0 First factor (x - 2)

x² + 10x + 9 = 0

(x + 9) (x + 1) = 0 polynomial of the form x² + bx + c

x³ + 8x² - 11x - 18 = (x - 2) (x + 9) (x + 1)