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9 November, 17:20

If alc and ab = c, prove that alb

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  1. 9 November, 20:51
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    This isn't true.

    Step-by-step explanation:

    Think of the case a=2, b=3 and c=6. We have that a|b, since 2|6.

    We also have that ab=c, since 2*3=6. However, it is NOT true that a|b, as 2 does NOT divide 3. As this you can construct many other examples where a|c and ab=c BUT a does NOT divide b.

    Other counterexamples:

    a=2, b=5, c=10

    a=2, b=7, c=14

    a=2, b=11, c=22

    a=2, b=13, c=26
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