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Mathematics
Maci Howe
15 October, 13:15
X+3y=3
2x-4y=6
solve the equations
+4
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2
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Donna Savage
15 October, 13:37
0
Subtract the second equation from double the first equation:
2x+6y-2x - (-4y) = 0
10y=0
Therefore, y=0. Substituting this into the first equation, we see that:
x+3 (0) = 3
x=3
Therefore, x=3. The solution to this system is x=3, y=0, or (3, 0).
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Jack Sawyer
15 October, 14:10
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So divide the second equation by 2
x-2y=3
the first equation is
x+3y=3
subsitute
3=3 so therefor
x-2y=x+3y
subtract x from both sides
-2y=3y
add 2y to both sides
0=5y
ofviously y=0 so subsitute
x-2y=3
x - (2) 0=3
x-0=3
x=3
x=3
y=0
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