A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A (t) remaining in the body t hours later is given by A (t) = 10 (0.7) t and that in order for the drug to be effective, at least 4 milligrams must be in the body.

a. Determine when 2 milligrams is left in the body.

b. What is the half-life of the drug?

Answer: a - 4.512 hours

b - 1.94 hours

Step-by-step explanation:

Given,

a) A (t) = 10 (0.7) ^t

To determine when 2mg is left in the body

We would have,

A (t) = 2, therefore

2 = 10 (0.7) ^t

0.7^t = 2:10

0.7^t = 0.2

Take the log of both sides,

Log (0.7) ^t = log 0.2

t log 0.7 = log 0.2

t = log 0.2 / 0.7

t = 4.512 hours

Thus it will take 4.512 hours for 2mg to be left in the body.

b) Half life

Let A (t) = 1/2 A (0)

Thus,

1/2 A (0) = A (0) 0.7^t

Divide both sides by A (0)

1/2 = 0.7^t

0.7^t = 0.5

Take log of both sides

Log 0.7^t = log 0.5

t log 0.7 = log 0.5

t = log 0.5/log 0.7

t = 1.94 hours

Therefore, the half life of the drug is 1.94 hours