Find two consecutive integers such that twice the larger is the same as two less than three times the smaller.

Ans = > 4, 5

Step-by-step explanation:

let the integers be x and y

if they are consecutive, that means the larger integer is one greater than the smaller

=> y = x+1

2 = 3x - 2y

3x - 2 (x+1) = 2

3x - 2x - 2 = 2

x = 4

y = 4+1 = 5