Two distinct number cubes, one red and one blue, are rolled together. Each number cube has sides numbered 1 through 6.

What is the probability that the outcome of the roll is a sum that is a multiple of 6 or a sum that is a multiple of 4?

Enter your answer, in simplest fraction form, in the box.

7/18

Step-by-step explanation:

First we need to find what values of sum we can have.

The minimum value for a cube is 1, so the minimum value for the sum is 2.

The maximum value for a cube is 6, so the maximum value for the sum is 12.

Now, we find the multiples of 6 and the multiples of 4 between 2 and 12:

4, 6, 8, 12.

To have a sum of 4, we can have the pairs:

(1,3), (2,2), (3,1)

To have a sum of 6, we can have the pairs:

(1,5), (2,4), (3,3), (4,2), (5,1)

To have a sum of 8, we can have the pairs:

(2,6), (3,5), (4,4), (5,3), (6,2)

To have a sum of 12, we can have the pairs:

(6,6)

So we have 14 pairs among the 36 (6 possibilities of each cube, so 6*6=36) total possibilities of pairs, so the probability is P = 14/36 = 7/18