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16 September, 16:21

At 8:00 AM a bicyclist departed city A, heading towards city B at a rate of 20 km/h. After traveling for 4 hours he stopped for an hour break. At the same time, a biker left city A traveling in the same direction at the rate of 50 km/h. How long will it take the biker to catch up to the cyclist?

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  1. 16 September, 18:12
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    2 hours and 40 minutes

    Step-by-step explanation:

    After 4 hours, 1st person went 20 * 4 = 80 km

    +1 hours rest

    So now after total 5 hours (when 2nd one started), 1st one is 80 km ahead.

    2nd bicyclist rate is 50

    1st bicyclist rate is 20

    So, for each hour, 2nd bicyclist advances 50 - 20 = 30 kilometers

    How long will it take him, at this rate, to catch up 80 kilometers?

    Simple!

    30 km catch up every hour, so

    80/30 = 2 2/3rd hours

    That would be 2 hours 40 minutes to catch up
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