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30 September, 09:49

Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻

A.) Can not be determined from the graph

B.) 2

C.) 0

D.) 1

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Answers (1)
  1. 30 September, 10:47
    0
    X^2+26=0

    So x^2=-26

    now x=squareroot (-26)

    Since the value of x is squareroot (-26) which is not a real number and is a imaginary number so roots does not exist for this equation.

    So option c 0 real roots is correct
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