Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 26.3 with a standard deviation of 4.9, while the 200 students in group 2 had a mean score of 15.9 with a standard deviation of 2.5.

Determine the 95% confidence interval for the difference in scores,?1 - ?2: (, ) (Round the variables to three decimal places as needed.)

A. (9.028, 11.572)

B. (9.328, 11.112)

C. (9.128, 11.102)

D. (9.628, 11.172)

Question

Zachery

18 September, 16:25

+4

Answers (1)

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Chandler · Answer 1

Answer: D

Step-by-step explanation:

The 95% confidence interval for the difference in scores is / left ({9.628,11.172} / right) (9.628,11.172).