A player pays $1 to play a game where three fair dice are rolled. If three 6s are obtained the player wins $500, and otherwise thr pkayer wins nothing. What are the expected net winnings of this game?

Ans: $1.31

(I need a solution!)

Question

Mathematics

Joey Roth

14 October, 20:27

A player pays $1 to play a game where three fair dice are rolled. If three 6s are obtained the player wins $500, and otherwise thr pkayer wins nothing. What are the expected net winnings of this game?

Ans: $1.31

(I need a solution!)

+2

Answers (1)

Know the Answer?

Gill · Answer 1

The chance to win = 1 : 6³ = 1 / 216

To win $500, the player needs to pay $216 on average.

500 / 216 = 2.31

$2.31 win and $1 cost per game gives $1.31 net win.

A player pays $1 to play a game where three fair dice are rolled. If three 6s are obtained the player wins $500, and otherwise thr pkayer wins nothing. What are the expected net winnings of this game?Ans: $1.31(I need a solution!)

A player pays $1 to play a game where three fair dice are rolled. If three 6s are obtained the player wins $500, and otherwise thr pkayer wins nothing. What are the expected net winnings of this game?

Ans: $1.31

(I need a solution!)