Ask Question
1 August, 22:20

The circumference of the inner circle is 66 ft. The distance between the inner circle and the outer circle is 44 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner circle? Use 22/7 for PI.

+2
Answers (1)
  1. 1 August, 22:43
    0
    276 4/7 ft

    Step-by-step explanation:

    Let r1 represent the radius of the inner circle. Then its circumference in feet is ...

    C = 2πr

    66 = 2π (r1)

    If the radius of the outer circle is (r1 + 44), then its circumference is ...

    C = 2π (r1 + 44) = 2π (r1) + 2π (44)

    C = 66 + 88π

    Then the difference in the circumferences is ...

    (66 + 88π) - (66) = 88π

    Using the given value of π, the difference in circumferences is ...

    (88 ft) (22/7) = 1936/7 ft = 276 4/7 ft
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The circumference of the inner circle is 66 ft. The distance between the inner circle and the outer circle is 44 ft. By how many feet is ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers