A polynomial has been factored below, but some constants are missing. 2x^3 - 6x^2 - 8x=ax (x+b) (x+c) What are the missing values of a, b, and c?

Question

Mathematics

Ariella Park

21 August, 14:02

A polynomial has been factored below, but some constants are missing. 2x^3 - 6x^2 - 8x=ax (x+b) (x+c) What are the missing values of a, b, and c?

+5

Answers (2)

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Kenya Mullins · Answer 1

Step-by-step explanation:

hello:

2x^3 - 6x² - 8x=ax (x+b) (x+c)

2x^3 - 6x² - 8x = 2x (x²-3x-4)

but : x²-3x-4 = (x+1) (x-4)

so : 2x^3 - 6x² - 8x = 2x (x+1) (x-4)

a=2 and b=1 and c = - 4

Antony Finley · Answer 2

2x (x - 4) (x + 1). A=2, B=-4, C=1