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18 February, 03:06

Factor 16x2 + 121 over the set of complex numbers.

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Answers (1)
  1. 18 February, 07:02
    0
    (4x - 11i) (4x - + 11i)

    Step-by-step explanation:

    Factor as a difference of squares

    a² - b² = (a - b) (a + b)

    note that i² = - 1

    Given

    16x² + 121

    = (4x) ² - (11i) ²

    = (4x - 11i) (4x + 11i)
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