Peter is saving to buy a camera. The camera costs $50. Peter has already saved $23.25. His plan is to save $4.50 every week to save at least enough for the camera. Write an inequality to model this situation.

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Mathematics

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15 February, 16:32

Peter is saving to buy a camera. The camera costs $50. Peter has already saved $23.25. His plan is to save $4.50 every week to save at least enough for the camera. Write an inequality to model this situation.

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Answers (1)

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Hadley Serrano · Answer 1

m ≥ 6

Here, m is the number of weeks Peter need to save money.

Step-by-step explanation:

The cost of the camera = $50

The amount of money already saved = $23.25

The money saved in 1 week = $4.50

Now, The TOTAL money LEFT to be saved = Total camera cost - Money already saved

= $50 - $23.25 = $26.75

So, there is $26.75 yet to be saved.

Let us assume it takes m weeks to save $26.75.

So, money saved in m weeks = m x (Money saved in 1 week)

or, $26.75. = m x ($4.50)

or, m = $26.75 / $4.50 = 5.94

or, m = 5.94 ≈ 6 weeks

So, the money saved in at least 6 weeks = $26.75.

Hence, it would take AT LEAST 6 weeks to save up enough amount to buy the camera which costs $50.

⇒ m ≥ 6