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28 December, 23:29

Find the limit as x approaches 25:

x-25

√x-5

+5
Answers (1)
  1. 29 December, 01:40
    0
    x - 25 = (√x) ^2 - 5^2 = (√x - 5) (√x + 5)

    Then

    (x - 25) / (√x - 5) = √x + 5

    and as x approaches 25, we get a limit of √25 + 5 = 5 + 5 = 10.
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