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14 July, 21:59

A function f (x) is said to have a removable discontinuity at x=a if: 1. f is either not defined or not continuous at x=a. 2. f (a) could either be defined or redefined so that the new function IS continuous at x=a. Let f (x) = { ((6) / (x) + (-5 x+18) / (x (x-3)), "if", x doesnt = 0 "and" x doesnt = 3), (3, "if", x=0) : } Show that f (x) has a removable discontinuity at x=0 and determine what value for f (0) would make f (x) continuous at x=0. Must redefine f (0) = ?

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  1. 15 July, 01:37
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    it would be 5
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