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8 October, 01:58

An automobile of mass 2 500 kg moving at 50.0 m/s is braked suddenly with a constant braking force of 8 500 N. How far does the car travel before stopping

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  1. 8 October, 05:09
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    367.64 meters

    Step-by-step explanation:

    Using the kinetic equation where:

    Vf ^ 2 - Vi ^ 2 = 2ax

    We know that:

    Vf = 0 m / s

    Vi = 50 m / s

    The acceleration can be calculated by means of F = M. a

    F = - 8500 (because it is stopping, braking force) and m = 2500 kg

    We have left that a = F / M = - 8500/2500 = - 3.4 m / s ^ 2

    Now reorganizing we have that:

    x = - Vi ^ 2 / 2a

    replacing the values is:

    x = - (50 ^ 2) / (2 * - 3.4) = 367.64 meters and this would be the distance the car travels when it stops.
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