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20 March, 10:55

What is the equation of the quadratic function that has a minimum at (7,-3) and goes through (9,9) ?

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  1. 20 March, 11:19
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    y = 3x² - 42x + 144

    Step-by-step explanation:

    The equation of a parabola in vertex form is

    y = a (x - h) ² + k

    where (h, k) are the coordinates of the vertex and a is a multiplier

    here (h, k) = (7, - 3), thus

    y = a (x - 7) ² - 3

    To find a substitute (9, 9) into the equation

    9 = 4a - 3 (add 3 to both sides)

    12 = 4a (divide both sides by 4)

    a = 3

    y = 3 (x - 7) ² - 3 ← in vertex form

    Expand factor and simplify

    y = 3 (x² - 14x + 49) - 3

    = 3x² - 42x + 147 - 3

    = 3x² - 42x + 144 ← in standard form
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