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Mathematics
Kathryn Hatfield
Yesterday, 22:27
Solve for x in the equation x2-12x+59=0.
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Camden Porter
Yesterday, 23:57
0
x1=6 + i4.80 x2=6 - i4.80
Step-by-step explanation:
Since 59 is a prime number we will use the quadratic formula to solve this problem:
x = (-b ± √ (b^2-4ac)) : 2a
Here a=1 b = - 12 c=59
Plugging these values in the formula:
x = (12 ± √ ((-12) ^2 - 4 (1) (59)) : 2 (1)
x = (12 ± √ (144 - 236)) : 2
x = (12 ± √-92) : 2
As we know that √-1 = i and √-92 can be written as √92 * √-1 so:
x = (12 ± i√92) : 2
x1 = (12 + i 9.59) : 2 x2 = (12 - i 9.59) : 2
x1=6 + i4.80 x2=6 - i4.80
The given equation has no real solutions, both are imaginary.
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