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25 November, 04:01

A plane leaves airport A and travels 560 miles to airport B on a bearing of Upper N 35 degrees Upper E. The plane later leaves airport B and travels to airport C 410 miles away on a bearing of Upper S 76 degrees Upper E. Find the distance from airport A to airport C to the nearest tenth of a mile

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  1. 25 November, 04:40
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    d₃ = 803.9 Miles

    Step-by-step explanation:

    d₁ = 560 Miles

    R₁ = N35⁰E

    d₂ = 410 Miles

    R₂ = S76⁰E

    d₃ = ?

    α = 35⁰+76⁰ = 111⁰

    We can apply the Law of Cosines as follows

    d₃ = √ (d₁² + d₂² - 2*d₁*d₂ * Cos α)

    ⇒ d₃ = √ (560² + 410² - 2*560*410 * Cos 111⁰) = 803.9 Miles
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Home » Mathematics » A plane leaves airport A and travels 560 miles to airport B on a bearing of Upper N 35 degrees Upper E. The plane later leaves airport B and travels to airport C 410 miles away on a bearing of Upper S 76 degrees Upper E.
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