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12 September, 09:42

According to TMUSS Quarterly (Totally Made-Up Sports Statistics) April 2017, the probability that the Tampa Bay Buccaneers will score a touchdown on their opening drive is 0.14. The probability that their defense will have 3 or more sacks in the game is 0.31. The probability that the Bucs will either score a touchdown on their opening drive or have 3 or more sacks in the game is 0.14. What is the probability that they will both score a touchdown on the opening drive and have 3 or more sacks in the game?

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  1. 12 September, 12:44
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    Answer: 0.31

    Step-by-step explanation:

    Let A denotes the event of Tampa Bay Buccaneers will score a touchdown on their opening drive and B denote the event that their defense will have 3 or more sacks in the game.

    Given : P (A) = 0.14 P (B) = 0.31 P (A or B) = 0.14

    Formula : P (A and B) = P (A) + P (B) - P (A or B)

    Now, the probability that they will both score a touchdown on the opening drive and have 3 or more sacks in the game will be : -

    P (A and B) = 0.14 + 0.31 - 0.14=0.31

    Hence, the required probability : 0.31
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