A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?

127 passengers

Step-by-step explanation:

THis is 127 passenger because if you add all this up and multiply by 2 then divide by 3 you get 127

2/9

Step-by-step explanation:

certain roller coaster has 3 cars

passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster.

First time a passenger can ride any car p=3/3 = 1

Second time the passenger should ride another car p=2/3;

Third time the passenger should ride not the 2 cars he had already driven: p=1/3.

so the probability that the passenger will ride in each of the 3 cars P = 1*2/3*1/3 = 2/9