Factor 56n^4+64n^3+70n^2+80n

n (7n + 8) (n^2 + 10)

Step-by-step explanation:

n is obviously a factor of every term. We also note that pairs of terms have coefficients in the ratio of 7 : 8, so (7n + 8) is another factor.

56n^4 + 64n^3 + 70n^2 + 80n = n ((7n + 8) n^2 + (7n + 8) ·10)

Then the factorization in integers is ...

= n (7n + 8) (n^2 + 10)