Ask Question
27 October, 01:00

Add: 3x (x-y+z) and 2y (x+y-z)

+1
Answers (2)
  1. 27 October, 02:09
    0
    3x^2 + 3xz + 2y^2 - 2yz - xy

    Step-by-step explanation:

    (1) multiply it to get

    3x^2 - 3xy + 3xz and 2yx + 2y^2 - 2yz

    add similar variables (-3xy + 2yx)

    (the order of the variables doesn't matter xy or yx is the same)

    we get - xy

    and then after that simplifying we get 3x^2 + 3xz + 2y^2 - 2yz - xy
  2. 27 October, 03:46
    0
    Step-by-step explanation:

    hello:

    3x (x-y+z) + 2y (x+y-z) = 3x²-3xy+3xz + 2yx+2y²-2yz

    3x (x-y+z) + 2y (x+y-z) = 3x² - xy+3xz - 2yz+2y²
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Add: 3x (x-y+z) and 2y (x+y-z) ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers