Kx - 3y = 4

4x - 5y = 7

In the system of equations above, k is a constant

and y are variables. For what value of k will

che sistem of equations have no solution?

k=12/5=2.4

Step-by-step explanation:

1. Let's get rid of the variable y

Multiply the first equation by 5 and the second by 3

5kx-15y=20

12x-15y=60

Now subtract from equation (2) / equation (1) - > 12x-5kx=40

x (12-5k) = 40 This equation is always solvable except if 12-5k=0, and this happens if k=12/5=2.4