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27 December, 13:35

If 2/√3+√5 + 5/√3-√5 = a√3 + b√5 find a and b

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  1. 27 December, 14:35
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    2/√3+√5 + 5/√3-√5 = a√3 + b√5

    Add fractions.

    7/√3+2√5

    To have √3 in numerator multiply both sides of raction by √3.

    (7√3) / 3+2√5 = a√3 + b√5, thus a = 7/3 and b = 2:

    Make sure you wrote the equation write, because Im not sure about that.
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