If 2/√3+√5 + 5/√3-√5 = a√3 + b√5 find a and b

2/√3+√5 + 5/√3-√5 = a√3 + b√5

Add fractions.

7/√3+2√5

To have √3 in numerator multiply both sides of raction by √3.

(7√3) / 3+2√5 = a√3 + b√5, thus a = 7/3 and b = 2:

Make sure you wrote the equation write, because Im not sure about that.