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7 September, 12:35

Tom is 77 inches tall and shrinking at a rate of 0.75% every eyar. How tall will he be after 15 years?

Whats the exponential function

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  1. 7 September, 14:22
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    The exponential funtion is "height (n) = 77 * (0.9925) ^n". After 15 years he is 68.7778 inches.

    Step-by-step explanation:

    Since Tom's initial height is 77 inches. After one year:

    height (1) = 77 * (1 - 0.0075) = 77*0.9925

    After two years:

    height (2) = height (1) * (0.9925) = 77*0.9925 * (0.9925) = 77 * (0.9925) ²

    After three years:

    height (3) = height (2) * 0.9925 = 77 * (0.9925) ²*0.9925 = 77 * (0.9925) ³

    And so on, therefore the expression that represents his height is:

    height (n) = 77 * (0.9925) ^n

    Where n is the number of elapsed years. For 15 years we have:

    height (15) = 77 * (0.9925) ^ (15) = 68.7778 inches

    The exponential funtion is "height (n) = 77 * (0.9925) ^n". After 15 years he is 68.7778 inches.
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