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30 July, 09:37

Two airplanes leave an airport at the same time. One airplane travels at 400 km/h

and the other at 525 km/h. After 2 hours, the planes are 900 km apart. Determine

the angle between their paths. Hint:

distance = (speed) (time)

+2
Answers (1)
  1. 30 July, 12:19
    0
    912.414

    Step-by-step explanation:

    The angle

    θ

    between the directions of motion of planes

    θ

    =

    320

    -

    200

    =

    120



    The distance

    a

    traveled by first plane flying at a speed of

    150

    km/hr

    in

    3

    hrs

    a

    =

    150



    3

    =

    450

    k

    m

    Similarly, the distance

    b

    traveled by second plane flying at a speed of

    200

    km/hr

    in

    3

    hrs

    b=

    200x3=

    600 km

    Now, the distance between the planes after 3

    hrs will be equal to the side of a triangle opposite to the angle θ=120∘

    included by the sides

    a

    =

    450

    & b=

    600

    .

    Now, using Cosine rule in the concerned triangle, the distance between the plane after

    3

    hours is given as
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