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8 September, 19:31

Prove or disprove: For any odd integer x, (x^2 - 1) is divisible by 8.

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  1. 8 September, 20:36
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    True

    Step-by-step explanation:

    To prove by induction, first show that the statement is true at an initial value (in this case, x = 1).

    8 | (1² - 1)

    8 | 0

    Next, assume the statement is true at x = k.

    8 | (k² - 1)

    Now show that it is true at the next value of x (x = k + 2).

    (k + 2) ² - 1

    = k² + 4k + 4 - 1

    = k² - 1 + 4 (k + 1)

    k + 1 is an even number, so 4 (k + 1) is a multiple of 8. And since we're assuming that k² - 1 is a multiple of 8, that means the sum is also a multiple of 8.

    8 | ((k + 2) ² - 1)

    So the statement is true.

    Logically, here's another way of proving it:

    x² - 1 = (x - 1) (x + 1)

    Since x is an odd integer, both x - 1 and x + 1 are even numbers. Since the difference between them is 2, one of them is a multiple of 4. An even number times a multiple of 4 is a multiple of 8.
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