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31 March, 09:04

Solve 2 (1/t^2) - 11 (1/t^2) + 15=0

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Answers (1)
  1. 31 March, 10:14
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    Answer: t=√3/5

    Step-by-step explanation:

    2 (1/t^2) - 11 (1/t^2) + 5=0

    Open the brackets

    2/t^2-11/t^2+5=0

    2-11+5t^2/t^2=0

    Cross multiply

    2-11+15t^2=0 (t^2)

    2-11+15t^2=0

    Collect like terms

    2-11=-15t^2

    -9=-15t^2

    t^2=-9/-15

    t^2=3/5

    t=√3/5
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