In attempting to calculate the carrying capacity of a cylindrical pipe, Avery measured the outer diameter to be 2 inches, neglecting to notice that the pipe was one eighth of an inch thick. By what percent did Avery overestimate the carrying capacity of the pipe?

Question

Mathematics

Zoey Frost

26 August, 10:19

In attempting to calculate the carrying capacity of a cylindrical pipe, Avery measured the outer diameter to be 2 inches, neglecting to notice that the pipe was one eighth of an inch thick. By what percent did Avery overestimate the carrying capacity of the pipe?

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Dustin · Answer 1

Volume of the pipe = πr^2l

Wrong measure = π x (2) ^2 x l = 4πl

Correct measure = π x (2 - 2 (1/8)) ^2 x l = 49/16πl

error = 4πl - 49/16πl = 15/16πl

% error = ((15/16πl) / 49/16πl) x 100% = 30.6%