Two equations are given below:

a - 3b = 28

a = b - 2

What is the solution to the set of equations in the form (a, b) ?

(-12, - 10)

(-15, - 13)

(-17, - 15)

(-18, - 16)

The best way to solve this problem is to plug and chug. it takes up time but is what needs to be done.

I will tell you though that it isn't (-12,-10)

Siince 2nd equation is already equal a, subsitute b-2 for a in the other equation

b-2-3b=28

-2-2b=28

add 2 to both sides

-2b=30

divide both sides by - 2

b=-15

sub back

a=b-2

a=-15-2

a=-17

(a, b)

(-17,-15)

3rd choice