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22 January, 09:11

The length and width of a rectangle lot are in the ratio 3 to 2. if he perimeter of the lot is 530yards, find the length and width

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  1. 22 January, 11:07
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    Length = l = 3x

    Width = w = 2x

    P = 2l + 2w

    P = 2 (3x) + 2 (2x)

    530 = 6x + 4x

    530 = 10x

    53 = x

    Length = 3x = 3 (53) = 318 / 2 sides = 159

    Width = 2x = 2 (53) = 212 / 2 sides = 106

    the length of the lot is 159 yards

    the width of the lot is 106 yards
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