Ask Question
9 November, 18:23

a car needw fixing and abe can fix it for $70 per hour with a $130 part, but gabe can fix it for $80 an hour with a $40 part. how long will it take for both abe and gabe to cost the same amount?

+5
Answers (2)
  1. 9 November, 18:50
    0
    The answer is 9

    Step-by-step explanation:

    (x represents the hours)

    130 + 70x = 40 + 80x

    70x - 80x = 40 - 130

    -10x = - 90

    -x = - 9

    x = 9
  2. 9 November, 21:02
    0
    70 + 130 = 200

    This would be Abe's one hour of work and the part

    80 + 80 + 40 = 200

    This would be Gabe's two hours of work and the part
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “a car needw fixing and abe can fix it for $70 per hour with a $130 part, but gabe can fix it for $80 an hour with a $40 part. how long will ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers