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25 May, 07:26

Write a polynomial that will have these solutions

x=3

2+3i

+4
Answers (1)
  1. 25 May, 07:31
    0
    p (x) = x³ - 7x² + 25x - 39

    Step-by-step explanation:

    complex roots occur as conjugate pairs, thus

    2 + 3i is a root then 2 - 3i is also a root

    given x = 3, x = 2 + 3i, x = 2 - 3i are roots, then

    (x - 3), (x - (2 + 3i)) (x - (2 - 3i)) are the factors and

    p (x) = a (x - 3) (x - 2 - 3i) (x - 2 + 3i) ← a is a multiplier

    let a = 1

    p (x) = (x - 3) ((x - 2) ² - 9i²)

    = (x - 3) (x² - 4x + 4 + 9) → [ i² = - 1 ]

    = (x - 3) (x² - 4x + 13)

    = x³ - 4x² + 13x - 3x² + 12x - 39

    = x³ - 7x² + 25x - 39
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