Two hamburgers and three cokes cost $10.50. Four hamburgers and four cokes cost $18.00. Find the cost of a hamburger and a coke.

Answer: hamburger $3.00

Coke $1.50

Step-by-step explanation:

2hamburgers & 3cokes = $10.50

4hamburgers & 4cokes = $18.00

Let hamburger represent H

And coke represent C

2H + 3C = 10.50 ... equation 1

4H+4C = 18.00 ... equation 2

2H = 10.50 - 3C ... equation 3

The 4H can be rewriting as

2 (2H) right

So substitute for the 4H

So we have,

2 (2H) + 4C = 18

Substitute for 2H

2 (10.50 - 3C) + 4C = 18

Open the bracket

21 - 6C + 4C = 18

21-2C = 18

-2C = 18-21

-2C = - 3

Minus cancel minus

C = 3/2 = $1.5

Substitute for c in equation 1

2H+3C = 10.50

2H+3 (1.5) = 10.50

2H+4.5=10.5

2H = 10.5-4.5

2H = 6

H = 6/2

H=$3

So

An hamburger cost $3.00

A coke cost $1.50