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27 December, 19:10

A student scored 84 and 87 on her first two quizzes. write and solve a compound equality to find the possible values for a third quiz score that would give her an average between 85 and 90, inclusive

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  1. 27 December, 19:30
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    Lower score

    [84 + 87 + x]/3 ≥ 85

    [84 + 87 + x]/3 = ≤90

    85 ≤ [171 + x]/3 ≤ 90

    255 ≤ 171 + x ≤ 270

    255 - 171 ≤ x ≤ 270 - 171

    84 ≤ x ≤ 99

    The solution is x | 84 ≤ x ≤ 99, which is the same that x belongs to [84,99]
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