the sum of three numbers is 144. the third number is 4 times the first. the second number is 6 more than the first. what are the numbers?

First I would change the descriptions of the numbers into expressions.

first number is n

second number is n + 6

third number is 4n (4 x n)

Then you would insert these expressions into an equation and isolate n.

n + n + 6 + 4n = 144

n + n + 4n = 144 - 6

6n = 138

n = 138/6

n = 23

Lastly, you would plug in this value into all of the expressions.

first number is 23

second number is 23 + 6 = 29

third number is 4 (23) = 92

Therefore, the numbers are 23, 29, and 92.