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2 August, 06:03

Ryan throws a baseball upward with an initial velocity of 12 m/s from a height of 2m above the ground. How long will it take for the baseball to hit the ground? Round answer to the nearest 10th of a second.

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  1. 2 August, 07:50
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    It will take 2.6 s for the ball to hit the ground.

    Step-by-step explanation:

    This is a standard physics problem

    The equation that defines the movement of Ryans baseball is given by the initial velocity, and the acceleration

    Distance = Do + Vo*t + 0.5*a*t^2

    Where

    Do is the initial distance.

    (Do = 2m over the ground)

    Vo is the initial velocity = 12m/s

    a is the acceleration that is exerted on the body (in this case a = g = - 9.8 m/s^2)

    t is the time

    We substitute in the equation, and solve for t (time)

    (0) = 2 + (12) * t + 0.5 * (-9.8) * t^2

    We get that

    t = 2.606 s = 2.6 s
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