Shelly is trying to improve her running time for a track race she ran the first race in 43.13 seconds her time was 43.1 seconds in the third race of this pattern continues what will Shelly time will be inthe fourth race

Question

Mathematics

Kaya Brooks

8 January, 03:57

Shelly is trying to improve her running time for a track race she ran the first race in 43.13 seconds her time was 43.1 seconds in the third race of this pattern continues what will Shelly time will be inthe fourth race

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Answers (2)

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Everett · Answer 1

I we consider her running times as an arithmetic series with common difference:

43.13 - 43.1 = -.03/2 = -.015, Shelly's time in the fourth race will be 43.1 -.015 = 43.085.

Shaun · Answer 2

The time in the fourth race is 43.04 seconds.

Step-by-step explanation:

Shelly's first race time is 43.13 seconds.

Shelly's second race times is 43.1 seconds.

Basically, she improved 0.03 seconds, because 43.13 - 43.1 = 0.03.

If she keeps this patterns that means she will improve 0.03 each race.

So, the third race times is 43.1 - 0.03 = 43.07 seconds.

The fourth race time is 43.07 - 0.03 = 43.04 seconds.

Therefore, the time in the fourth race is 43.04 seconds, because she's improving at a constant rate of 0.03 seconds per race.