As of a certain date, 94,696 of the four-character sequences using either letters or digits had not yet been claimed. If a four-character name is randomly selected on that date, what is the probability that it is already owned? (Round your answer to four decimal places.)

Question

Mathematics

Salazar

14 January, 20:33

As of a certain date, 94,696 of the four-character sequences using either letters or digits had not yet been claimed. If a four-character name is randomly selected on that date, what is the probability that it is already owned? (Round your answer to four decimal places.)

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Answers (1)

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Ivy Cooke · Answer 1

Hence the probability that are already owned are 0.943620

Step-by-step explanation:

Given:

No fo character sequences using either letter or digits had not been claimed=94696

To find:

What is probability that letter are already claimed?

Solution:

We know that there are 26 alphabets and digits are 0,1,2 ... 9

Hence total will be of 36.

Now we are going to Arrange the sequence for all possible values

as there 4 characters we get, each of them with 36 possible values

=36*36*36*36

=36^4

=1679616.

Now we have a sequence with 94696 character and digits are not claimed.

Its probability

=94696/1679616

=0.05637.

So the required probability will be,

P (claimed) = 1 - P (Not claimed)

= 1-0.056379

=0.943620

Hence the probability that are already owned are 0.943620