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19 April, 09:58

Using the quadratic formula to solve 4x^2-3x + 9=2x + 1 what are the values of x

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  1. 19 April, 11:32
    0
    x=5±√-103/8

    Step-by-step explanation:

    There's no real solutions

    4x2-3x+9 - (2x+1) = 2x+1 - (2x+1)

    4x2-5x+8=0

    x=-b±√b2-4ac/2a

    x = - (-5) ±√ (-5) 2-4 (4) (8) / 2 (4)

    x=5±√-103/8
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