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3 July, 01:57

The st. joe company grows pine trees and the average annual increase in tree diameter is 3.1 inches with a standard deviation of 0.5 inch. a random sample of n = 50 trees is collected. what is the probability of the sample mean being less the 2.9 inches?

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  1. 3 July, 05:04
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    Solution: We are given:

    μ=3.1,σ=0.5, n=50

    We have to find P (Mean <2.9)

    We need to first find the z score

    z = (xbar-μ) / (σ/sqrt (n))

    = (2.9-3.1) / (0.5/sqrt (50))

    = (-0.2) / 0.0707

    =-2.83

    Now we have to find P (z<-2.83)

    Using the standard normal table, we have:

    P (z<-2.83) = 0.0023

    Therefore the probability of the sample mean being less the 2.9 inches is 0.0023
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