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6 November, 15:43

Mary has been offered two jobs. Job a has a starting salary of 36,000 and a raise of 1500 every year. Job B has a starting salary of 29,000 and a raise of 2500 every year. In how many years would Mary's salary be the same at both companies. What would that salary be?

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  1. 6 November, 18:26
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    Number of year Mary's salary be the same at both = 7 year

    Equal salary amount = 46,500

    Step-by-step explanation:

    Given:

    Starting salary in job A = 36,000

    Gain per year in job A = 1,500

    Starting salary in job B = 29,000

    Gain per year in job B = 2,500

    Find:

    Number of year Mary's salary be the same at both = ?

    Equal salary amount = ?

    Computation:

    Assume : in x year salary from job A is equal to salary from job B

    Salary from job A in x year = 36,000 + 1,500 x ... Eq1

    Salary from job B in x year = 29,000 + 2,500 x ... Eq2

    From Eq1 and Eq2

    36,000 + 1,500 x = 29,000 + 2,500 x

    7,000 = 1,000 x

    x = 7 Year

    Number of year Mary's salary be the same at both = 7 year

    From Eq1 ...

    Equal salary amount = 36,000 + 1,500 (7)

    Equal salary amount = 36,000 + 10,500

    Equal salary amount = 46,500
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