6 November, 15:43

# Mary has been offered two jobs. Job a has a starting salary of 36,000 and a raise of 1500 every year. Job B has a starting salary of 29,000 and a raise of 2500 every year. In how many years would Mary's salary be the same at both companies. What would that salary be?

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1. 6 November, 18:26
0
Number of year Mary's salary be the same at both = 7 year

Equal salary amount = 46,500

Step-by-step explanation:

Given:

Starting salary in job A = 36,000

Gain per year in job A = 1,500

Starting salary in job B = 29,000

Gain per year in job B = 2,500

Find:

Number of year Mary's salary be the same at both = ?

Equal salary amount = ?

Computation:

Assume : in x year salary from job A is equal to salary from job B

Salary from job A in x year = 36,000 + 1,500 x ... Eq1

Salary from job B in x year = 29,000 + 2,500 x ... Eq2

From Eq1 and Eq2

36,000 + 1,500 x = 29,000 + 2,500 x

7,000 = 1,000 x

x = 7 Year

Number of year Mary's salary be the same at both = 7 year

From Eq1 ...

Equal salary amount = 36,000 + 1,500 (7)

Equal salary amount = 36,000 + 10,500

Equal salary amount = 46,500